GB0-381-ENU試験無料問題集「H3C Large-Scale Routing Network Technologies V2.0 認定」

In the topology shown in the figure, configuration needs to be done on the RTA to import the default route in the OSPF area.

Which of the following configurations can achieve the above goals?

正解:A,B,D 解答を投票する
As shown in the figure, RTB, RTC and RTA establish IBGP peers, and RTA is the reflector of RTB and RTC. Currently RTA and RTC are egress routers connecting to the Internet. In order to make RTB access the Internet through RTA or RTC, a default route is configured on RTA and RTC, and advertised using the network command.
Which of the following statements is correct is _____.

The PBR configuration on a router is as follows.
policy-based-route pbr_a permit node 10
if-match acl 3000
apploutput-interface serial 2/0
policy-based-route pbr_a dennode 20
if-match acl 3000
Assuming the policy has been successfully applied, how will the data flow configured with Acl3000 on this router be forwarded?

In the IS-IS network as shown in the figure, the configuration of the authentication part of each router is as follows
RTA-Serial2/0]isis authentication-mode md5 h3c
RTB-isis-1]area-authentication-mode md5 h3c
RTC-isis-1]domain-authentication-mode md5 h3c
Then RTA and RTB______ synchronize LSDB, and RTB and RTC______ synchronize LSDB.

The router uses the Router-ID to generate the NET address of the IS-IS process. The benefits are ______.

正解:B,C,D 解答を投票する
Regarding the OSPF protocol, the following statement is correct is _______.

RTA and RTB establish an IS-IS adjacency relationship on a P2P type link as shown in the figure. The figure is a schematic diagram of RTB from running IS-IS to sending CSNP. Then the message types of messages 1 to n may be ______.

The RIP protocol is enabled on a router, the process number is 1, and the priority is 10; at the same time, the OSPF protocol is enabled, the process number is 100, and the priority is 100. If two processes learn the route of network segment 10.0.0.0/8 at the same time, the metric values ​​are 1 (hop count) and 100 (cost value) respectively, and the next hops are 1.0.0.1 and 1.0.0.2 respectively.
After the router receives the packet with the destination address 10.0.0.1, what should it do?

Features of distance vector routing protocols include ________. (select one or more)

In the network shown in the figure, the default next hop of PTA is RTC, and the configuration of PBR is as follows:
policy-based-route pbr_a permit node 10
if-match acl 3000
appldefault output-interface serial 2/0
policy-based-route pbr_a dennode 20
According to the above configuration, what is wrong about the data stream matching Acl 3000 on the RTA?

Execute the following command on the MSR router RTA:
RTA-GigabitEthernet0/0]ip address 192.168.1.1 24
RTA-GigabitEthernet0/0]uit
RTA]router id 2.2.2.2
RTA]ospf 1 router-id 1.1.1.1
RTA-ospf-1]uit
RTA]interface LoopBack 0
RTA-LoopBack0]ip address 3.3.3.3 32
From the above configuration, it can be judged that the Router ID of OSPF process 1 of RTA is ______

In BGP protocol packets, the unreachable route information is advertised through ______.

Running the command on the router and its display information is as follows:
<RTC>displisis lsdb level-1 verbose
Database information for ISIS(1)
--------------------------------
Level-1 Link State Database
LSPID Se Num Checksum Holdtime Length ATT/P/OL
-------------------------------------------------- -----------------------------
3333.3333.3333.00-00* 0x0000007c 0x5fae 388 58 1/0/0
SOURCE 3333.3333.3333.00
NLPID IPV4
AREA ADDR 02
INTF ADDR 10.1.3.2
INTF ADDR 10.3.4.1
NBR ID 4444.4444.4444.00 COST: 10
3333.3333.3333.00-01* 0x0000008f 0x55ae 388 113 0/0/0
SOURCE 3333.3333.3333.00
IP-Internal 10.1.3.0 255.255.255.252 COST: 10
IP-Internal 10.3.4.0 255.255.255.252 COST: 10
IP-Internal* 172.16.3.1 255.255.255.255 COST: 10
IP-Internal* 10.1.2.0 255.255.255.252 COST: 20
IP-Internal* 192.168.18.0 255.255.255.0 COST: 30
IP-Internal* 172.16.2.1 255.255.255.255 COST: 20
IP-Internal* 172.16.1.1 255.255.255.255 COST: 20
4444.4444.4444.00-00 0x00000111 0x9817 1098 62 1/0/0
SOURCE 4444.4444.4444.00
NLPID IPV4
AREA ADDR 02
INTF ADDR 10.3.4.2
INTF ADDR 10.2.4.2
INTF ADDR 172.16.4.1
NBR ID 3333.3333.3333.00 COST: 10
4444.4444.4444.00-01 0x0000006f 0x8952 1098 65 0/0/0
SOURCE 4444.4444.4444.00
IP-Internal 10.3.4.0 255.255.255.252 COST: 10
IP-Internal 10.2.4.0 255.255.255.252 COST: 10
IP-Internal 172.16.4.1 255.255.255.255 COST: 0
From the above information, we can know that __________.

正解:A,B,D 解答を投票する